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authorJérémy Zurcher <jeremy@asynk.ch>2022-03-25 09:37:06 +0100
committerJérémy Zurcher <jeremy@asynk.ch>2022-03-25 09:37:06 +0100
commit623c5d60f54c62fd50d115859cf60ea41785d5d2 (patch)
treea1a08cbd3795cab502aa53efc5de4a3dec11f447 /05-advanced_algorithms_and_complexity/02-linear_programming/02-diet
parent7b224832b3795baaa5334f5f8f352c7aec330ae5 (diff)
downloadcoursera-623c5d60f54c62fd50d115859cf60ea41785d5d2.zip
coursera-623c5d60f54c62fd50d115859cf60ea41785d5d2.tar.gz
Algorithms : complete 05-advanced_algorithms_and_complexity 02-linear_programming
Diffstat (limited to '05-advanced_algorithms_and_complexity/02-linear_programming/02-diet')
-rw-r--r--05-advanced_algorithms_and_complexity/02-linear_programming/02-diet/diet.cpp205
1 files changed, 196 insertions, 9 deletions
diff --git a/05-advanced_algorithms_and_complexity/02-linear_programming/02-diet/diet.cpp b/05-advanced_algorithms_and_complexity/02-linear_programming/02-diet/diet.cpp
index efe4e89..7e1056a 100644
--- a/05-advanced_algorithms_and_complexity/02-linear_programming/02-diet/diet.cpp
+++ b/05-advanced_algorithms_and_complexity/02-linear_programming/02-diet/diet.cpp
@@ -1,21 +1,208 @@
#include <algorithm>
+#include <limits>
#include <iostream>
#include <vector>
#include <cstdio>
using namespace std;
+// #define DEBUG
+
typedef vector<vector<double>> matrix;
-pair<int, vector<double>> solve_diet_problem(
- int n,
- int m,
- matrix A,
- vector<double> b,
- vector<double> c) {
+void print(matrix A, vector<double> b)
+{
+#ifdef DEBUG
+ for (int i = 0; i < A.size(); i++) {
+ for (int j = 0; j < A[0].size(); j++) {
+ cerr << A[i][j] << " ";
+ }
+ cerr << ": " << b[i] << endl;
+ }
+ cerr << endl;
+#endif
+}
+
+#define DELTA 0.000001
+static inline bool same(double a, double b)
+{
+ double d = (a - b);
+ return (d < 0 ? -d : d) < DELTA;
+}
+
+void gaussian_elimination(matrix& m)
+{
+ int rows = m.size();
+ int cols = m[0].size();
+ int np_row = 0;
+
+ // each column
+ for (int col = 0; col < (cols - 1); col++) {
+ // each non-pivot row
+ for (int row = np_row; row < rows; row++) {
+ // leftmost non-zero
+ if (m[row][col] != 0) {
+ // swap row with np_row
+ if (row != np_row)
+ std::swap(m[np_row], m[row]);
+
+ vector<double>& pivot_row = m[np_row];
+ // scale pivot row
+ if (pivot_row[col] != 1.0) {
+ double f = 1.0 / pivot_row[col];
+ for (int i = 0; i < cols; i++)
+ pivot_row[i] *= f;
+ }
+
+ // scale then add to non-zero other rows
+ for (int i = 0; i < rows; i++) {
+ if (i != np_row && m[i][col] != 0) {
+ vector<double>& r = m[i];
+ double f = r[col] / pivot_row[col];
+ for (int j = 0; j < cols; j++)
+ r[j] -= pivot_row[j] * f;
+ }
+ }
+
+ np_row++;
+ break;
+ }
+ }
+ }
+}
+
+#define BIG_NUM 1000000000
+#define BEST -std::numeric_limits<double>::max()
+
+pair<int, vector<double>> solve(
+ matrix A,
+ vector<double> b,
+ vector<double> c)
+{
+ int cstrs = A.size(); // n
+ int vars = A[0].size(); // m
+
+ matrix M(vars, vector<double>(vars + 1));
+ double best = BEST;
+ vector<double> sol(vars);
+
+ // build permutations of A
+ int nbits = 0;
+ int v = 0;
+ int max = (1 << cstrs) - 1;
+ vector<bool> bits(cstrs, false);
+
+ bool augmented = false; // will be set to true when the last constraint is used
+
+ // for each permutation of size vars
+ for (int v = 0; v < max; v++) {
+ // build next value
+ for (int i = 0; i < bits.size(); i++) {
+ if (!bits[i]) {
+ bits[i] = true;
+ nbits++;
+ break;
+ }
+ bits[i] = !bits[i];
+ nbits--;
+ }
- // Write your code here
+#ifdef DEBUG
+ cerr << "####" << v + 1 << " : ";
+ for (int i = 0; i < bits.size(); i++)
+ cerr << bits[i] << " ";
+ cerr << endl;
+#endif
+
+ if (nbits != vars)
+ continue;
+
+ if (!augmented && bits[bits.size() - 1]) {
+ // no solution found so far
+ if (same(best, BEST))
+ return {-1, sol}; // no solution
+ augmented = true;
+ }
+
+ // build matrix to solve
+ int x = 0;
+ for (int i = 0; i < bits.size(); i++) {
+ if (bits[i]) {
+ for (int j = 0; j < vars; j++)
+ M[x][j] = A[i][j];
+ M[x][vars] = b[i];
+ x++;
+ }
+ }
+
+ print(M, b);
+ gaussian_elimination(M);
+ print(M, b);
+
+ bool ok = true;
+
+ // check that solution matrix pivots are 1's
+ for (int i = 0; i < vars; i++) {
+ if (!same(M[i][i], 1.0)) {
+ ok = false;
+ break;
+ }
+ }
+ if (!ok)
+ continue;
+
+ // check that other inequalities holds
+ for (int i = 0; i < bits.size(); i++) {
+ if (!bits[i]) {
+ double r = 0;
+ for (int j = 0; j < vars; j++)
+ r += (M[j][vars] * A[i][j]);
+ if (r > (b[i] + DELTA)) {
+ ok = false;
+ break;
+ }
+ }
+ }
+ if (!ok)
+ continue;
+
+ // compute fitness
+ double r = 0;
+ for (int j = 0; j < vars; j++)
+ r += (M[j][vars] * c[j]);
+ if (r > best) {
+ if (augmented)
+ return { 1, sol}; // infinity, see last paragraph in What To Do
+ best = r;
+ for (int j = 0; j < vars; j++)
+ sol[j] = M[j][vars];
+ }
+ }
+
+ if (same(best, BEST))
+ return {-1, sol}; // no solution
+
+ return {0, sol};
+}
+
+pair<int, vector<double>> solve_diet_problem(
+ int n,
+ int m,
+ matrix A,
+ vector<double> b,
+ vector<double> c)
+{
+ // add m constraints : -var <= 0
+ for (int i = 0; i < m; i++) {
+ vector<double> v(m, 0);
+ v[i] = -1;
+ A.push_back(v);
+ b.push_back(0);
+ }
+ // add augmented constraint : sum vars < BIG_NUM
+ A.push_back(vector<double>(m, 1));
+ b.push_back(BIG_NUM);
- return {0, vector<double>(m, 0)};
+ return solve(A, b, c);
}
int main(){
@@ -45,7 +232,7 @@ int main(){
case 0:
printf("Bounded solution\n");
for (int i = 0; i < m; i++) {
- printf("%.18f%c", ans.second[i], " \n"[i + 1 == m]);
+ printf("%.14f%c", ans.second[i], " \n"[i + 1 == m]);
}
break;
case 1: